Apartment for rent in Amsterdam - Theo Frenkelhof
Available immediately
€ 2,400 p/m
87m²
3 rooms
We found this offer for you today on the web. Due to technical reasons, we therefore have limited information and photos available. Would you like to know more about this offer? Then respond now and your response will be with the landlord immediately! The landlord or broker can give you more information.
Newly build, unfurnished two bedroom unit (approx. 90m2) on IJburg!
LAYOUT
Elevator to 4th floor. Private balcony. Spacious hallway, bright living room with half open kitchen with build-in appliances (oven, fridge/freezer, induction cooking and dishwasher). The apartment counts two decent size bedrooms. One bedroom equipped with a bed and closets. Modern bathroom with walk-in shower and a sink. Separate toilet and laundry room. On the ground floor you'll find your private storage room.
LOCATION
This new condo is located at Theo Frenkelhof, Haveneiland, (IJburg). A calm and quiet location, at the marina and with great food and beverage options nearby. IJburg shopping center is steps away. Amsterdam-Pampus-Muiderslot ferry service leaves from the port. For a walk or run Diemerpark is just minutes away.
The accessibility of the apartment is good: The highway-system can be reached quickly via IJburglaan and exit S114. Street parking available. High-speed tram line 26 (Central Station) and bus lines 66 (Station Bijlmer Arena) and 289 (Central Station) have a stop at nearby IJburglaan. The Nescio Bridge provides a fast bicycle connection from IJburg to Diemen, Watergraafsmeer and Zuidas.
DETAILS
- Rental amount is excluding utilities;
- Available 21-01-2025;
- Deposit equals 2 months rent;
- Washing machine and curtains provided;
- Model B contract; max. 24 months.
Price
€ 2,400 per month
Floor area
87m²
Rooms
3
Available
Immediately indefinitely
Provider
Broker / Corporate Landlord
Register municipality
Yes
Internet
Yes
Respond now and your response will be with the landlord immediately!
How does responding at Kamer.nl work?